Inch Stroke 12
Inch Stroke 12
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 12 inch300mm stroke linear actuator 330LBS 12V 24V 36V DC  US $72.00
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 10 inch250mm stroke linear actuator 330LBS 12V 24V 36V DC US $70.00
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 4 inch stroke linear actuator 330LBS 12V 24V 36V DC US $67.00
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 Linear Actuator 6 inch stroke 200 lbs 12VDC US $131.99
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 Linear Actuator 14 inch stroke 400 lbs 12 VDC US $133.99
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 Linear Actuator 12 inch stroke 400 lbs 12 VDC US $131.99
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 Linear Actuator 4 inch stroke 400 lbs 12 VDC US $131.99
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 Linear Actuator 12 inch stroke 150 lbs force 12 VDC US $118.99
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 Linear Actuator 6 inch stroke 50 lbs force 12 VDC US $118.99
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 Linear Actuator 22 inch stroke 250 lbs 12 VDC US $80.00
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 Linear Actuator 14 inch stroke 250 lbs 12 VDC US $75.00
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 Linear Actuator 24 inch stroke 200 lbs 12 VDC US $139.99
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 Linear Actuator 18 inch stroke 400 lbs 12 VDC US $139.99
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 Linear Actuator 18 inch stroke 200 lbs 12 VDC US $139.99
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 Linear Actuator 10 inch stroke 200 lbs 12 VDC Progressive Automations US $131.99
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 Linear Actuator 10 inch stroke 400 lbs 12 VDC US $131.99
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 Linear Actuator 9 inch stroke 400 lbs 12 VDC US $131.99
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 Linear Actuator 9 inch stroke 200 lbs 12 VDC Progressive Automations US $131.99
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 Linear Actuator 8 inch stroke 400 lbs 12 VDC US $131.99
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 Linear Actuator 8 inch stroke 200 lbs 12 VDC Progressive Automations US $131.99
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 Linear Actuator 6 inch stroke 400 lbs 12 VDC US $131.99
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Chem problem: Gas law?
In a diesel engine the fuel is ignited when it is injected into hot compressed air, heated by the compression itself. In a typical high-speed diesel engine, the chamber in the cylinder has a diameter of 10.7 cm and a length of 13.4 cm. On compression, the length of the chamber is shortened by 12.7 cm (a “5-inch stroke”). The compression of the air changes its pressure from 1.00 to 38.7 atm. The temperature of the air before compression is 322 K. As a result of the compression, the final air temperature will be _____________ K just before the fuel injection.
Can someone please help me answer this?????????? I really need your help! Thanks in advance!
Let cross sectional area = A
Diameter does not change, therefore A does not change.
V1 = A*(13.4cm)
V2 = A*(13.4cm-12.7cm) = A*(0.7cm)
P1=1.00atm
P2=38.7atm
T1=322
P1 V1/T1 = P2 V2/T2
T2 = T1*(P2/P1)*(V2/V1)
T2 = 322*(38.7/1.00)*((A*0.7)/(A*13.4)) = 651 K
Ans: 651 K
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